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54 lines
2.4 KiB
SQL
54 lines
2.4 KiB
SQL
-- 默认任务开放范围调整:平台默认/学校默认只默认开放第一个项目的前 3 个任务。
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--
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-- 背景:此前平台默认(class_id='999999999')与学校默认(class_id LIKE 'SCHOOL_DEFAULT:%')
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-- 的任务目录默认全部开放,与产品约定不一致——任务分配的默认口径是
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-- "教学班未保存发布配置时,仅默认开放第一个项目的前三项,不是全部任务"。
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--
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-- 影响范围:只调整 disabled_status,不增删任务、不改 module/sort;
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-- 第一个项目的前 3 项置为开放(0),其余任务(含综合实训)置为停用(1)。
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-- 学校管理员仍可在"默认实训任务配置"页按需放开。
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--
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-- 前置条件:task_allocation.module 已是英文 task_key,即已执行
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-- 2026-10-16-repair-task-allocation-module-keys.sql
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-- 若仍有中文任务名残留,JOIN 不上的行保持原值,请先执行修复脚本重建。
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--
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-- 幂等:可重复执行。执行前建议备份:
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-- CREATE TABLE task_allocation_bak_20261016_first3 AS
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-- SELECT * FROM task_allocation
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-- WHERE class_id='999999999' OR class_id LIKE 'SCHOOL_DEFAULT:%';
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-- 1) 第一项目前 3 项开放,其余启用目录内的任务置为停用
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UPDATE task_allocation a
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JOIN training_task t ON t.task_key = a.module
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JOIN (
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SELECT task_key,
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ROW_NUMBER() OVER (ORDER BY sort ASC, id ASC) AS rank_in_project,
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COALESCE(project_name, '其他') AS project_name
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FROM training_task
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WHERE enabled = 1
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AND task_key <> 'comprehensive-case-training'
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) ranked ON ranked.task_key = a.module
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CROSS JOIN (
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SELECT COALESCE(project_name, '其他') AS project_name
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FROM training_task
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WHERE enabled = 1 AND task_key <> 'comprehensive-case-training'
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ORDER BY sort ASC, id ASC
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LIMIT 1
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) fp
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SET a.disabled_status = CASE WHEN ranked.project_name = fp.project_name
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AND ranked.rank_in_project <= 3
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THEN 0 ELSE 1 END
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WHERE a.class_id = '999999999' OR a.class_id LIKE 'SCHOOL_DEFAULT:%';
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-- 2) 综合实训始终默认停用(各班发布后才参与)
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UPDATE task_allocation
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SET disabled_status = 1
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WHERE (class_id = '999999999' OR class_id LIKE 'SCHOOL_DEFAULT:%')
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AND module = 'comprehensive-case-training';
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-- 3) 校验:每个 class_id 下应只有 3 条开放(即第一个项目的前 3 项)
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SELECT a.class_id, SUM(a.disabled_status = 0) AS open_count, COUNT(*) AS total
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FROM task_allocation a
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WHERE a.class_id = '999999999' OR a.class_id LIKE 'SCHOOL_DEFAULT:%'
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GROUP BY a.class_id;
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